Algorithm/BFS, DFS
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등촌동 꼬북이
2020. 9. 24. 18:07
말이 되고픈 원숭이 문제를 풀었다면
아주 쉬운 문제
import sys
from collections import deque
def bfs():
visited[0][0][1] = 1
que = deque()
que.append([0, 0, 1])
while que:
x, y, k = que.popleft()
if x == N - 1 and y == M - 1:
return visited[x][y][k]
for i in range(len(direction)):
nx = x + direction[i][0]
ny = y + direction[i][1]
if 0 <= nx < N and 0 <= ny < M:
if k and mapData[nx][ny] and not visited[nx][ny][k - 1]:
que.append((nx, ny, k - 1))
visited[nx][ny][k - 1] = visited[x][y][k] + 1
if not mapData[nx][ny] and not visited[nx][ny][k]:
que.append((nx, ny, k))
visited[nx][ny][k] = visited[x][y][k] + 1
return -1
direction = [[-1, 0], [1, 0], [0, 1], [0, -1]]
N, M = map(int, input().split())
mapData = [[0] * M for _ in range(N)]
visited = [[[0 for i in range(2)] for i in range(M)] for i in range(N)]
for i in range(N):
temp = sys.stdin.readline()
for j in range(M):
mapData[i][j] = int(temp[j])
print(bfs())